JEE MAIN - Physics (2022 - 25th June Morning Shift - No. 4)
If force $$\overrightarrow F = 3\widehat i + 4\widehat j - 2\widehat k$$ acts on a particle position vector $$2\widehat i + \widehat j + 2\widehat k$$ then, the torque about the origin will be :
$$3\widehat i + 4\widehat j - 2\widehat k$$
$$ - 10\widehat i + 10\widehat j + 5\widehat k$$
$$10\widehat i + 5\widehat j - 10\widehat k$$
$$10\widehat i + \widehat j - 5\widehat k$$
คำอธิบาย
$$\overrightarrow \tau = \overrightarrow r \times \overrightarrow F $$
$$ = (2\widehat i + \widehat j + 2\widehat k) \times (3\widehat i + 4\widehat j - 2\widehat k)$$
$$ = - 10\widehat i + 10\widehat j + 5\widehat k$$